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What are the solutions of the system? y=x+5 y=x^2-x+2
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Combine the equations to get: \[x^{2} -2x -3 = y. \]
Oops, I meant set them equal to each other.
Since you have y equal to two different expressions in x, set the two expressions equal to each other. \(x + 5 = x^2 - x + 2\) Now bring all terms to the left side, and solve the quadratic equation in x. Then substitute each solution in the first original equiation to get a y value. You should end up with two ordered pairs.
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