Question

Find all solutions in the interval [0, 2π).

sec^2 x - 2 = tan^2 x

answers:
No solution

x = pi/3

x = pi/6

x = pi/4

2. Find the inverse of the function.

(function in comments)

answers:

f-1(x) = 6(x+7)3

f-1(x) = 6(x3 + 7)

f-1(x) = 18(x + 7)

f-1(x) = [6(x+7)]3

Someone please help me out, I am taking my segment exam and need to make a good grade.

Answer 1

\[^3\sqrt{x/6}- 7\]

Answer 2

magic

Answer 3

.....