Question

The length of a rectangle is 5mm longer than its width. Its perimeter is 30mm. let w equal the width of the rectangle.

Answer 1

2(W + L) = 30
2(W + W + 5) = 30
W = 5
L = 10

Answer 2

Okay well we know the total perimeter of a rectangle is

2L + 2W = P

we know P = 30 so

2L + 2W = 30

now we are also given that the length of the rectangle is 5mm longger than the width

So

L = W + 5

so

2L + 2W = 30
L = W + 5

2 equations...2 unknowns....can you solve this?

Answer 3

still need help !!

Answer 4

Alright...well if you look at the equation equation...we see that L = W + 5

Well since we know that 'L' equals THAT...we can substitute that into the first equation...
So everytime you see L in the first equation...replace it with (W + 5)

2L + 2W = 30
would become
2(W + 5) + 2W = 30

Distribute out the 2...

2W + 10 + 2W = 30

Can you go on from here?