Question

log (x^2-36) -1= log (x+6)
Solve for X.

Answer 1

Okay i know that you have to do 10^log (x^2-36) -1= 10^log (x+6)

Answer 2

and then the logs cancel out,

Answer 3

The base is 10, so we don't need to take that out right now. First put the -1 on the other side.
log(x^2-36)-1=log(x+6)
log(x^2-36)-log(x+6)=1
log[(x^2-36)/(x+6)]=1
Heres a clearer view.

Do you understand so far?