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Statistics 9 Online
OpenStudy (anonymous):

To analyze the quality of the packaging at a fertilizer factory, 100 '50-lb' bags are randomly selected. If the expected weight of each bag is 50 lbs and the variance is 1, then the probability that the sample mean is between 49.75 lbs and 50.15 lbs is equal to?

OpenStudy (mathmale):

Hi, Bzinkie, Start by identifying your sample size: n = ? Sample mean: x-bar = ? Sample std. dev.: S = ? z-score for each 49.75 and 50.15? Hint: z-score = (x - x-bar)/[S/Sqrt(n)] What additional info need you to complete the solution of this problem?

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