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Mathematics 14 Online
OpenStudy (beccaboo333):

can i have help?

OpenStudy (beccaboo333):

Select one of the factors of 3x2 + 12x - 36

OpenStudy (beccaboo333):

A. 6 B. x + 2 C. x + 6 D. x - 3

OpenStudy (beccaboo333):

the 2 is one of the little numbers i forget the proper name

OpenStudy (anonymous):

Ok say what again?

OpenStudy (beccaboo333):

3x2 + 12x - 36 the 3x(2) the 2 is an exponent or something like that.

OpenStudy (beccaboo333):

not really sure if that made any sense

OpenStudy (helder_edwin):

u can use synthetic division or replace -a in case of x+a and see if u get a zero

OpenStudy (beccaboo333):

whaaaa?

OpenStudy (helder_edwin):

ok. u have x+2, if u put x+2=0 u get x=-2 right?

OpenStudy (beccaboo333):

i guess...

OpenStudy (helder_edwin):

u guess?? ok replace x=-2 in the polynomial: \[\large 3x^2+12x-36=3(-2)^2+12(-2)-36=3\cdot4-24-36 \] \[\large =12-24-36=-48 \] which is not zero, so x+2 is not a factor got it?

OpenStudy (beccaboo333):

not really

OpenStudy (anonymous):

she praticlly told you the answer you just need to study, it

OpenStudy (beccaboo333):

dont post if you're not gonna help. i have to teach myself everything. guess what?! i have a hard time. seriously

OpenStudy (anonymous):

okay okay, remember i'm just going to try.

OpenStudy (helder_edwin):

which ways of factoring a polynomial did u learn?

OpenStudy (anonymous):

3x2+12x−363(x(2)+4x−12)3(x+6)(x−2)

OpenStudy (beccaboo333):

i dont even know..

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