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help please find f(f^-1(-8)), where f(x)=x^3 - 6
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Find the inverse of f(x), first.
y = x^3 - 6 x = y^3 - 6 solve for y.
actually, from the definition of the inverse of a function \[\large f(f^{-1}(-8))=(f\circ f^{-1})(-8)=-8 \]
Why find the inverse? The inverse is also a 1-to-1 function with no confusion for Domain or Range. \(f(f^{-1}(-8)) = -8\)
so f(f^-1(-8))= what
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We DO have to be careful first to notice that the inverse is ALSO a function WITHOUT any restriction on Domain or Range.
oh mb.
okay got it thanks
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