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Mathematics 16 Online
OpenStudy (anonymous):

how do i do this? find domian and range

OpenStudy (timaashorty):

Find domain and range of what ?

OpenStudy (anonymous):

\[f(x)=\sqrt{x+\frac{ 1 }{x-5 }}\]

OpenStudy (helder_edwin):

for the domain solve the inequation \[\large x+\frac{1}{x-5}\geq0 \]

OpenStudy (anonymous):

D=X greater or equal to 5

OpenStudy (helder_edwin):

no do the addition on the left, first

OpenStudy (anonymous):

1/2 (5- square root 21) less than or equal to x less than or equal 1/2 (5+ square root 21)

OpenStudy (helder_edwin):

\[\large \frac{x(x-5)+1}{x-5}\geq0 \] \[\large \frac{x^2-5x+1}{x-5}\geq0 \]

OpenStudy (helder_edwin):

then solve \[\large x^2-5x+1=0 \] and \[\large x-5=0 \]

OpenStudy (anonymous):

yeah thats what i have

OpenStudy (helder_edwin):

i got \[\large \left[\frac{5-\sqrt{21}}{2},\frac{5+\sqrt{21}}{2}\right]\cup(5,+\infty) \]

OpenStudy (anonymous):

i have the first one i forgot to do the last one

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