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whats y = -3(x-2)(x+3)
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you mean in standard form?
yes
well then, it's the same concept as before standard form of parabola: y = ax^2 + bx + c so just foil and distribute
y = -3(x-2)(x+3) = -3(x^2+x-6) then distribute the negative 3
if you're not sure how to foil http://www.freemathhelp.com/using-foil.html
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i got y= -6 +21
-.- y = -3x^2 -3x + 18
lol idk tf im doing
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