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Calculus1
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A pipeline is to be built to cross a 0.5km wide river and reach a point which is 6km down the river on the opposite bank. it cost 50% more to build across the river than on land. How should the pipeline be routed in order to minimize cost?
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c(x) = 1.5m √(x² + 0.5²) + m(6-x), where m is the cost (a constant), where (6-x) is the distance away from the point on the bank. Graph and x = 1/√(5) will minimize the cost. 6 - 1/√(5) is the distance away from the point on the bank
ok i think i understand what you did. just wondering how you got 1.5
if m is the cost for land then (m + 0.5m) = 1.5m is the cost for water
thanks. this clears things up alot :)
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