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Mathematics 21 Online
OpenStudy (anonymous):

lim x →0 4x/tan2x

OpenStudy (tkhunny):

Have you considered: \(\dfrac{4x}{\tan(2x)} = \dfrac{4x}{\dfrac{\sin(2x)}{\cos(2x)}} = 2\cos(2x)\cdot\left(\dfrac{2x}{\sin(2x)}\right)\)?

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