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OpenStudy (anonymous):
Solve. (4-3i)(2+2i)
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OpenStudy (anonymous):
\[i ^{2}=-1\] now foil (4-3i)(2+2i)
OpenStudy (anonymous):
8+8i-6i-6(-1)= 8+2i+6=14+2i
OpenStudy (anonymous):
thanks! so it's basically just the foil method?
OpenStudy (kc_kennylau):
yep :) and don't forget that \(i^2=-1\) :)
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