what is the series equation of e^(-x^2)
I have the expansion: 1-(x^2/1!)+(x^4/2!)-(x^6/3!)+...
I know it is an alternating series so it will start with (-1)^n but I am making note cards for my exam so I need to make sure I have the equation right!

@agent0smith

Question

what is the series equation of e^(-x^2)
I have the expansion: 1-(x^2/1!)+(x^4/2!)-(x^6/3!)+...
I know it is an alternating series so it will start with (-1)^n but I am making note cards for my exam so I need to make sure I have the equation right!

@agent0smith

anonymous · Answer

$$e ^{x}=1+\frac{ x }{ 1! }+\frac{ x ^{2} }{2! }+\frac{ x ^{3} }{ 3! }+..........$$
$$put x=-x ^{2}$$
you are doing correctly.

megannicole51 · Answer

what is the sum equation?