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OpenStudy (anonymous):
Which expression is equivalent to 1+cot^2X?
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OpenStudy (anonymous):
cot = cos/sin
OpenStudy (anonymous):
Thank you @JuanitaM
OpenStudy (anonymous):
\[\csc ^{2}x-\cot ^{2}x=1 so 1+\cot ^{2}x=\csc ^{2}x\]
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