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5. ABCD is rectangle. Find m
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130 degrees 165 degrees 150 degrees 90 degrees
;D
it is 130 degree. as in the figure AD II BC and AC is transversal. so, <DAC = < BCA ( corresponding angles) <BCA+<DCA = 90 <DCA=90-<BCA =90-65 =25 Since in a rectangle the diagonals bisect equally so, EC = ED So <EDC=<ECD for the triangle ECD <ECD+<EDC+<DEC=180 <DEC=180-<ECD+<EDC =180-25+25 =130 degree Option A is correct.
@baddiemaddie understood it ???
Got it, thanks!
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