Question

(5-i)^6 expressed in trigonometric form and De Moivre's theorem

Answer 1

5-i=root(5^2+1^2) exp(I theta)
tan theta = -1/5

Answer 2

Would theta end up as -11.31?

Answer 3

yes th=-11.309932

Answer 4

So would it end up as 6623.9+16280.0i?

Answer 5

yes

Answer 6

Thanks

Answer 7

your welcome
you did it by your self