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OpenStudy (anonymous):
Tell whether the function is a proportional relationship. y = x + 1
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OpenStudy (anonymous):
OpenStudy (isaiah.feynman):
Yes it does.
OpenStudy (mertsj):
is it of the form y = kx?
OpenStudy (anonymous):
@Mertsj I'm not sure.
OpenStudy (mertsj):
Well you wrote y = x+1 In y = kx, I don't see anything added to the x, do you?
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OpenStudy (anonymous):
@Mertsj What do you mean?
OpenStudy (mertsj):
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