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Write an equation in point slope form given: slope, m, = -1/5 and point (5, -2).
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\[-2-y _{1}=m(5-x _{1})\]
A. y + 2 = -(1/5)(x - 5) B. y + 5 = -(1/5)(x - 2) C. y – 5 = (1/5)(x + 2) D. y – 5 = (1/5)(x - 2)
y - y1 = m(x - x1) slope(m) = -1/5 (5,-2) x1 = 5 and y1 = -2 now we sub y - 5 = -1/5(x - (-2) y - 5 = -1/5(x + 2) <=== point slope form
wait...I messed up,,,hold on
y - y1 = m(x - x1) y - (-2) = -1/5(x - 5) y + 2 = -1/5(x - 5)
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sorry about that....I put the points in the wrong spot
answer is : y + 2 = -1/5(x - 5)
any questions ?
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