Question

if vector a cross vec b=2i+j and a.b=5 then the angle between vec a and vec b is ...................
a.tan t =5^1/2
b.tan t=1/(5^1/2)

Answer 1

|axb| = |ab sin (t) |

|a.b| = |ab cos (t) |

Answer 2

take the ratio

Answer 3

|axb |
----- = ?
|a.b|

Answer 4

tan t=2i+j/5 ..................... how i get the angle

Answer 5

you need to take |axb| which is the length of axb

Answer 6

axb = 2i+j

|axb| = ?

Answer 7

k, now i became able of solving MAY ALLAH GIVE YOU REWARD OF IT

Answer 8

good to knw :)