Question

what is the value of the expression
6x-1[7-2(3x-10)]

Answer 1

Simplifying
6x + -1[7 + -2(3x + -10)]

Reorder the terms:
6x + -1[7 + -2(-10 + 3x)]
6x + -1[7 + (-10 * -2 + 3x * -2)]
6x + -1[7 + (20 + -6x)]

Combine like terms: 7 + 20 = 27
6x + -1[27 + -6x]
6x + [27 * -1 + -6x * -1]
6x + [-27 + 6x]

Reorder the terms:
-27 + 6x + 6x

Combine like terms: 6x + 6x = 12x
-27 + 12x

Answer 2

forgot to add this on end when x=5

Answer 3

a.-27
b.-17
c.13
d.33
e.87

Answer 4

@LanguageEnthusiast

Answer 5

\[6\times5-1 (7-2 (3\times5-10))\]
Use BODMAS. (Bracket, orders, division, multiplication, addition, subtraction.)
\[6×5-1 (7-2 (15-10))\]
Subtract 10 from 15.
\[6×5-1 (7-2×5)\]
\[6×5-1 (7+-10)\]
\[6×5-1×-3\]
\[30-1 (-3)\]
\[30+3\]
\[30+3 = 33:\]
\[33\]

Answer 6

oh ok ive never learned bomdas only pemdas

Answer 7

They are exactly the same, only in Britain we use BODMAS.
The question is relatively simple just sub in five where x is, then use BODMAS/PEMDAS to solve for your answer.

Answer 8

thanks

Answer 9

No problem, glad to be of help :-).