Mathematics
7 Online
OpenStudy (anonymous):
Algebra help please!
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OpenStudy (anonymous):
What's the question?
OpenStudy (anonymous):
hold on @zeinas.
OpenStudy (anonymous):
K
OpenStudy (anonymous):
1 : B & D
2 : A
3 : C
OpenStudy (anonymous):
For number 1, we know that we need two numbers that multiply to -10, and add to -9. And they are -10 and +1, so
(x+10)(x-1)
So it will be A, D
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OpenStudy (kattan):
1 : B & C
2 : C
OpenStudy (anonymous):
what bout 2 & 3?
OpenStudy (raden):
-9 = -10 + 1
-10 = -10 * 1
@zeinas.
OpenStudy (anonymous):
wat would answer b?
OpenStudy (kattan):
1 : B & C
2 : C
3 : B&C
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OpenStudy (anonymous):
For 2, I'm not sure., the numbers are +14, and +3, which means the polynomial should be:
14 *3=42, and
14+3=17
x^2+17x+42
@RadEn what do you think?
OpenStudy (anonymous):
And three is B and C.
OpenStudy (raden):
-14 * -3 = 42
-14 + (-3) = -17
OpenStudy (anonymous):
so 1 : B & C 2 C 3 is B?
OpenStudy (kattan):
3: B&C
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OpenStudy (anonymous):
@RadEn....The factors are (x-14)(x-3)
If the factors were -14 and -3, it would be
(x+14)(x+3)....It's a weird question
OpenStudy (raden):
1 and 2 are correct, 3 still incomplete
OpenStudy (anonymous):
3 cant be B & C it has to be one
OpenStudy (raden):
kattan is right, 3 B and C
x^2 + 6x + 8 = (x+2)(x+4)
OpenStudy (anonymous):
B & D & A?
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OpenStudy (anonymous):
@kattan help ?
OpenStudy (anonymous):
1. will be d) (x+3)
OpenStudy (anonymous):
what bot rest? @zeinas.
OpenStudy (anonymous):
2. c.(4x-1) It took me awhile because I was working it out, and
3. a. (2x-1)