What is the speed period, and radial acceleration of a communications satellite in a circular orbit 2000km above the surface of the earth. The earth's radius is 6380 km and its mass is 5.98 x 10^24 kg. G = 6.67 x 10^-11 Nm^2kg^-2. At what height above the surface of the earth should the satellite be placed for the orbital speed to be 5000 m/s?

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anonymous · Answer

@douglaswinslowcooper Hey bro if you aren't busy I would really appreciate it if you could take a look at this problem

anonymous · Answer

Strategy: match the gravitational acceleration F/gravity with the centripetal acceleration= v^2 / r. 

Gravitational acceleration = G M / r^2,

where M is mass of earth, G is gravitational constant, and r is the distance of the object from the Earths center (height plus Earth's radius). 

Plug and chug. I'm nearly in bed.

anonymous · Answer

Hope it worked out OK.