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Mathematics 21 Online
OpenStudy (lovelycharm):

Given the equation Square root of 2x plus 1 = 3, solve for x and identify if it is an extraneous solution

OpenStudy (lovelycharm):

\[\sqrt{2x+1}=3\]

OpenStudy (anonymous):

1st step...square both sides. Now what does the equation look like?

OpenStudy (lovelycharm):

wat

OpenStudy (lovelycharm):

x = 4, solution is extraneous x = 4, solution is not extraneous x = 5, solution is extraneous x = 5, solution is not extraneous

OpenStudy (anonymous):

Square both sides.. That means raise each side to the 2nd power.|dw:1387142715598:dw|

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