Question

Solve x^2/3-3x^1/3-10=0

Answer 1

\[x ^{2/3}-3x ^{1/3}-10=0\]

Answer 2

\[put x ^{\frac{ 1 }{3 }}=y,x ^{\frac{ 2 }{3 }}=y ^{2}\]

Answer 3

huh?

Answer 4

let
x^1/3 = y
and
x^2/3 = y^2
so

y^2 - 3y - 10 = 0
(y-5)(y+2) = 0
sub back in

(x^1/3 - 5)(x^1/3+2) = 0
make sense?

Answer 5

either y-5=0,y=5,
\[x ^{\frac{ 1 }{3 }}=5,cubing x=5^{3}=125\]
similarly find for other.