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Algebra
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how do you solve x^3 - 8 ??????
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x^3 - 8 = 0 x^3 = 8 take the cubed root of both sides x = 2
Thank You! so when you are taking the cubed root out of 8 all you're doing is dividing it by 3?
no. \[\huge \sqrt[3]{8} = 2\]
the cubed root of a number means what value to the power of 3 makes this value?
for example \[\huge \sqrt[3]{64} = 4 , 4^3 = 64\]
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okay..can you tell me how to type that into a graphing calculator if possible??
or is it just something where i have to try my luck to find the answer?
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