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Mathematics 19 Online
OpenStudy (pixiedust1):

=

OpenStudy (anonymous):

Well post the question and we'll see what we can do

OpenStudy (anonymous):

question

OpenStudy (anonymous):

For something perpendicular I believe it would be the reverse and negative of whatever the slope of the original is, so in this case it would be -1/2

OpenStudy (anonymous):

-1/2

OpenStudy (anonymous):

I believe that would be y= x+2

OpenStudy (pixiedust1):

Can you tell me why you would think that?

OpenStudy (anonymous):

y=x+2

OpenStudy (anonymous):

Well for that one you could just try plugging the x on the given point into where the x is on the equations and manually do it to find the y

OpenStudy (pixiedust1):

Okay! thank you

OpenStudy (anonymous):

No problem

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