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Math Help Please..
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I can work the first one (number 20) for you and you will do the rest, OK?
\[17x-15=12\]\[17x-15\color{red} {+15}=12\color{red} {+15}\]\[17x=27\]\[17x\color{red} {\div 17}=27\color{red} {\div 17}\]\[x=27/17\]
\[17~\color{red} {(27/17)}~-15=12\]\[27-15=12\]\[12=12\]
See how I did it, try to do the rest, if anything wrong we will correct you.
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Okay
Tell me what you get for each when you do it....
I still dont quite understand how to do number 21, i dont get it
How to solve this problems. 1) Eliminate x and it's coefficient by itself 2) Divide both sides by the coefficient of x.
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