Question

Need help with this indefinite integral.

Answer 1

What is it

Answer 2

\[\int\limits_{a}^{b} h(x)dx=3a+ b then, \int\limits_{a}^{b} [h(x) +2]dx= ??\]

Answer 3

\[\int\limits_{a}^{b} h(x)dx=3a+ b\]
\[\int\limits_{a}^{b} [h(x) +2]dx= \int\limits_{a}^{b} [h(x) ]dx + \int\limits_{a}^{b} +2dx=\] 3a + b + 2b -2a =a + 3b

Answer 4

Now I see it! THANK YOU!