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how to solve compound inequality
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5x+10>(or equal to) 10 and 7x-7 <(orequalto) 14
i don't understand how to do it exactly.
5x + 10 >= 10 -- subtract 10 from both sides 5x >= 10 - 10 5x >= 0 -- divide by 5 x >= 0/5 x >= 0 7x - 7 <= 14 -- add 7 to both sides 7x <= 14 + 7 7x <= 21 -- divide by 7 x <= 3 so we have x greater or equal to 0 and x less then or equal to 3 which can be written like : 0 <= x <= 3
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any questions ?
thank you sooooooooo much!!!
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