Question

logx^1/81=-4

Answer 1

log property that might help:

\[log x^{y} = {y}log x \]

Answer 2

thank you what about x^-4=1/81

Answer 3

So if you are still referring to the last problem, I don't think thats right. From the log property I gave you above you get this:
\[\frac{1}{81} \log x = -4\]
then you should get this:
\[\log x = -324 ==> 10^{-324} = x\]