Solve this system of equations using substitution, elimination or graphing. Show all of your work for the method you choose. y = 6x – 4 y = -2x + 28
Well, we can see that y and y are very similar. Multiply a -1 to the top equation and then cancel out the y. That is your first step.
ok
You should have 0=-6x+4 0=-2x+28
Now you can add them together to get 0=-8x+32
Bring 32 over to the other side to get -32 = -8x. Can you solve x from here?
do I divide -8 on both sides @KirbyLegs
Yes you do. then the -8 will cancel out leaving you with 4 = x
ok thats what I got! Thanks :)
simply u can use double substitution method.. two different values of y are given. is you will equate it then you will get the value of x y = 6x – 4 y = -2x + 28 y=y 6x-4=-2x+28 transfer the like terms to one side 6x+2x=28+4 8x=32 x=4 put the value in any eq you will get y y=6(4)-4 =20 x=4 y=20
ohh
yup....
thats interesting! thanks :)
no problem thanks..
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