Question

PLEASE HELP I GIVE MEDALS!

Simplify (2m^2 n^-3)^4

Answer 1

\[(2m^2 n^{-3})^4\]this?

Answer 2

\[(2m^{2 \times 4}n^{-3 \times 4})\]\[(2m^{8}n^{-12})\]
being that \[a^{-b}=\frac{1}{a^b}~~~~~~~~~~~~~~~~there fore\]\[n^{-12}=\frac{1}{n^{12}}\]\[\frac{2m^8}{n^{12}}\]

Answer 3

Makes sense?