Question

what are the solutions of the system y=x^2-6x+7 and y=-x+13

Answer 1

equate them
x^2-6x+7 = -x+13
this is a quadratic in x
can you find 2 values of x from this ?

Answer 2

a.) (-1,14) and (6,7)
b.) (-1,7) and (6,14)
c.) (-1,13) and (6,7)
d.) no solutions

I am leaning more towards C or D?

Answer 3

@hartnn

Answer 4

did u try to solve that quadratic ?

Answer 5

Uhh I don't really know how to solve quadratic

Answer 6

x^2-6x+7 = -x+13
x^2 -6x +x +7 -13 = 0
x^2 -5x -6 = 0

can u tell me 2 numbers whose sum is -5 and product = -6

Answer 7

3 and 2

Answer 8

well hmm wait that doesn't work because uh a - times a - in a + but -3 +2 will not be -5

Answer 9

yeah
try once more :)

Answer 10

-6 and 1

Answer 11

YES!

Answer 12

so,
i split -5x as -6x+x

Answer 13

x^2 -6x +x -6 = 0
x (x-6) +1 (x-6) = 0
(x-6) (x+1) = 0

got this ??
can u proceed ?

Answer 14

I don't think you can continue I mean yeah x=-6 and x=1 but that answer isn't showing here so will it be no solution?

Answer 15

not actually
x-6 = 0
gives you x= 6
x+1 = 0
gives you x = -1

Answer 16

so, find the value of y when x=6
y = -x +13
y = -6 + 13 =.. ?

Answer 17

Ahh so it is opposite...I think I get it now. and y= -6+13=0?

Answer 18

-6+13 is +7
so one of your point is 6,7

Answer 19

ahh okay...and how will i solve for the other point with the -1?

Answer 20

y = -x +13
y = -(-1) + 13
y = 1+13 = 14
so other point = -1,14

Answer 21

Woo thanks so much :)

Answer 22

welcome ^_^

Answer 23

Can I have more help?

Answer 24

sure,
just ask new question in new post :)