Question

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Answer 1

5. How many real number solution does this equation have?
y=-4x^2+7x-8
a. no solutions
b. one solutions
c. two solutions
d.infinetely solutions.


6. how many real number solution does this equation have?
-8x^2-8x-2=0
a.one solutioin
b. two solutions
c. no solutions
d. infintely many solutions

9. Find the solutions in the system
y=x^2-5x+2
y=-6x+4
a. (2,8) and (-1, 2)
b. (-2,8) and (1,-2)
c. (-2,16) and (1,-2)
d. No solutions

10. Find the solutions to the system
y=x^2+8x+2
y=7x+4
a. (-2,-10) and (1,11)
b. (2,10) and (-1,-11)
c. (-2,-34) and (1,11)
d. no solutions

Answer 2

Part of the problem is listing several questions.

Let's take number 6. Multiply by -1 to make all the coefficients positive. Standard form is ax^2 + bx + c = 0

divide by 8 for convenience, so it is x^2 + x + 1/4 = 0

solutions are x = [-b +- sqrt[b^2-4 a c] ]/ 2 a

a=1, b = 1, c=1/4 which means that b^2-4ac=0 so the square root is 0 and you have only one solution, x = -b / 2a = 1/2

Handle the others similarly.