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How to find the vertex (x+4)(5x+2) so confused someone help me
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foil the binomial and consider the standard quadratic formula Ax^2+Bx+C=0 vertex= \[(-\frac{ b }{ 2a },f(-\frac{ b }{ 2a }))\]
equation not formula
Right...so expand your 2 factors into a quadratic...and you'll take the 'b' value and divide it by 2 times the 'a' value... what is (x + 4)(5x + 2) when expanded?
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