Question

compute the difference quotient of 2x^2+4x-1
a)4x+4
b)2x+2h+2
c)4x+2h+4
d)4x-2h-4

Answer 1

\[\frac{\left(2(x+h)^2+4(x+h)-1\right)-\left(2x^2+4x-1\right)}{h}\\
\frac{2x^2+4xh+2h^2+4x+4h-1-2x^2-4x+1}{h}\\
\frac{4xh+2h^2+4h}{h}\\
4x+2h+4
\]