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64^4x=16^x+4 Please Help!
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\[64^4x=16^{x+4}\] is that it?
no i mean\[64^{4x}=16^{x+4}\]
divide both sides by 16^x+4: \[4^{10x-8}=1\]
take log base 4 of both sides so you get: \[10x-8=0\] and now you can solve it by yourself
you can also solve it by writing it as : \[4^{3*4x}=4^{2(x+4)}\] then: \[3*4x=2(x+4)\] and solved as normal
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Thanks a bunch I was stuck on that one for awhile
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