Question

what is x in log(6x+5)-log2=log5

Answer 1

any ideas? have you tried this?

Answer 2

separate the logs first

Answer 3

log 6x+log 5-log2=log5

Answer 4

bring over log 5 to right side cancels

Answer 5

log 6x=log2

Answer 6

log 6 +log x= log 2

Answer 7

logx=log2-log6

Answer 8

logx=log(2/6)

Answer 9

logx=log(1/3)

Answer 10

have you finished?

Answer 11

no haven't finished yet

Answer 12

so whats x?

Answer 13

x=10^(log(1/3))

Answer 14

which is?

Answer 15

If you're method was correct then x=1/3
what does your answer book say?

Answer 16

i get 1/3 when i punch it into the calculator

Answer 17

what answer book :S

Answer 18

dont you have answers at the back of the book?

Answer 19

I'm just doing these questions off the top of my head i'm a university student :P

Answer 20

wow, are you doing uni maths?

Answer 21

yup i miss high-school and elementary school math its easy compared to what i have to do now T.T

Answer 22

nice try, but the method is incorrect.

log laws

1. log(ab) = loga + logb
2. log(a/b) = loga - logb
3. if loga = logb, then a=b

Answer 23

so for log(6x+5) - log2 = log5

we have log[(6x+5)/2] = log5

therefore (6x+5)/2 = 5

and 6x+5 = 10

6x = 5

hence x = 5/6

Answer 24

i need to brush up on these old skills

Answer 25

yes, you do

Answer 26

if you're doing uni maths you need to know your basics inside out

Answer 27

trust me u lose a couple of things down the road cuz i hardly touched upon logs and when u look back its way diff

Answer 28

i understand. same thing happened to me when i did uni maths.
i think it was series at the time

Answer 29

I'm in good hands then this website is going to be perfect to answering any math questions i may have :D

Answer 30

yeah its a pretty good site

Answer 31

thanks for the medal