Question

Help me on trigonometry please!

Multiple choice question 6, how would I simplify it?

Answer 1

U can't open it

Answer 2

pi=180
http://www.purplemath.com/modules/idents.htm

Answer 3

any luck coolsday?

Answer 4

\[\huge\color{blue}{\frac{2Cot(90)-k}{1-Tan^2k} }\]

Answer 5

\[\huge\color{blue}{Cot(90)=\frac{Cos(90)}{Sin(90)}=\huge\color{blue}{\frac{0}{1}=0 } }\]

Answer 6

\[\huge\color{blue}{\frac{-k}{1-Tan^2k} }\]

Answer 7

\[lets~~~~work~~~~the~~~~\huge\color{blue}{1-Tan^2x }\]

Answer 8

\[\huge\color{blue}{1-\frac{Sin^2k}{Cos^2k} }\]\[\huge\color{blue}{\frac{Cos^2k}{Cos^2k}-\frac{Sin^2k}{Cos^2k} }\]

Answer 9

\[\huge\color{red}{1 \over\frac{Cos^2x-Sin^2x}{Cos^2x}} \]\[\huge\color{red}{\frac{Cos^2x}{Cos^2x-Sin^2x}} \]

Answer 10

\[1-Cot^2k\]