Question

please help!

If the numerator of a fraction is increased by 3, the fraction becomes 3/4. If the denominator is decreased by 7, the fraction becomes 1.

What is the numerator of the fraction?


2
9
16

Answer 1

\[\frac{y}{x+3}=\frac{3}{4}\]\[\frac{y}{x-7}=1\]

you can conclude.\[y=x-7\]So,\[\frac{x-7}{x+3}=\frac{3}{4}\]cross multiplication.\[4(x-7)=3(x+3)\]\[4x-28=3x+9\]SOLVE FOR x
then tell me what x+3 is going to be equal to.

Answer 2

x=37

Answer 3

then do i just plug in 37 in to x+3??

Answer 4

to find the denominator yes.

Answer 5

but im trying to find the numerator;

Answer 6

oh, then plug x=37 into
x-7

Answer 7

You might want to go over my work...

Answer 8

but then its not in one of the options... ):

Answer 9

then idk.