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Find all zeros of the function and write the polynomial as a product of linear factors. f(x)=x^4+6x^3+12x^2+24x+32 a.) f(x)=(x-1)(x-8)(x-2i)(x+2i) b.) f(x)=(x-i√8)(x+i√8)(x-2)(x+2) c.) f(x)=(x-2)(x+4)(x-2)(x+2) d.) f(x)=(x+2)(x+4)(x-2i)(x+2i) Please, show all works.
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if you plug 1 into f(x) , do you get 0 ?
no.
so, get rid of the first option, right?
try the second one, pick the easiest case, x = 2 from (x-2) =0, is f(2) =0?
but it all positive so it can't equal to 0.
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if you can see it, very good, safe time, just have the last one which have negative value, try.
f(-2) = 0?? f(-4) =0 ??
f(-2) is equal to 0.
good,
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