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Geometry 8 Online
OpenStudy (anonymous):

Find the value of x and y

OpenStudy (anonymous):

|dw:1387309299856:dw|

OpenStudy (anonymous):

HELP!!!

OpenStudy (anonymous):

Let a^2+b^2=c^2.....

OpenStudy (anonymous):

a triangle must equal 180 degrees!....

OpenStudy (anonymous):

How do you know you've got a right angle?

OpenStudy (anonymous):

Britclev...is there a right angle in the picture

OpenStudy (anonymous):

but for this you will be using sin, cos, and tan!!!!!.

OpenStudy (anonymous):

no right angle

OpenStudy (anonymous):

you can remember these through an acronym.....:"SOHCAHTOA"

OpenStudy (anonymous):

SOH... Sine: sin(θ) = Opposite / Hypotenuse ...CAH... Cosine: cos(θ) = Adjacent / Hypotenuse ...TOA Tangent: tan(θ) = Opposite / Adjacent

OpenStudy (anonymous):

I cant figure out an exaxt answer for the life of me

OpenStudy (anonymous):

|dw:1387268294597:dw|

OpenStudy (anonymous):

ok

OpenStudy (mathstudent55):

Is KM a diameter?

OpenStudy (anonymous):

you can create a right triangle

OpenStudy (mathstudent55):

Without any other information, the most you can say about x and y is x + y = 140

OpenStudy (anonymous):

|dw:1387268452231:dw|

OpenStudy (anonymous):

y = 180 - 40 - x, 140-y x = 180 - 40 -y, 140-x

OpenStudy (anonymous):

you dont know that it is a right triangle therefore Pythagorean is out. you cannot solve for any lengths, not enough info provided. y =140-x x=140-y

OpenStudy (jdoe0001):

BRITCLEV can you post a quick screenshot of the picture?

OpenStudy (phi):

Did they (by any chance) mention that KM is a *diameter* ?

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