What is the length of the mid segment of the trapezoid made by the vertices A(0,5) B(3,3) C(5,-2) and D(-1,2). Show equations and all work that leads to your answer. Help Please:s

Question

anonymous · Answer

@SolomonZelman Helpp Please

solomonzelman · Answer

That's a lot of work...

anonymous · Answer

Indeed it is :s

solomonzelman · Answer

Distance formula.
$$d=\sqrt{(y_1-y_2)^2+(x_1-x_2)^2}$$

I would suggest drawing it first.

solomonzelman · Answer

(If I make an attachment, it would take a while.)

solomonzelman · Answer

I don't have a right program to draw it, can you draw it?

anonymous · Answer

distance formula d² = ( x2- x1)² + ( y2-y1)² 
segment AB 
D²(AB)= (3-0)² + (3-5)²= 9+4=13 
D AB = √ 13 
midpoint will divide the segment in half, thus each half has a length of 
D (AB)/ 2 = √(13)/2 
I dont know

anonymous · Answer

I will try and see if If theres one on the internet, wait a sec