Question

3(t-14)-5(t+12)

Answer 1

can u sistribute everything first?

Answer 2

distribute

Answer 3

\[a(b-c)=(a \times b)-(a \times c)\]THis is the way to do it, apply it here.

Answer 4

ok

Answer 5

\[AND\]\[a(b+c)=(a \times b) + (a \times c)\]

Answer 6

tell me what you get when you're done.

Answer 7

umm ill try

Answer 8

go ahead, sure...

Answer 9

but the B in the answer will be a T what to do about tht

Answer 10

is it (3*t)+(3*12)

Answer 11

\[3(t-14)-5(t+12)\]Lets work the first part\[3(t-14)\]\[(3 \times t)-( 3 \times 14)\]\[3t-42\]Now the second part\[-5(t+12)\]\[(~~(-5) \times t)+(~~(-5) \times 12)\]\[-5t-60\]so so far you have \[3t-42\color{red} {-5t-60}\](second part is in red)

Answer 12

ok

Answer 13

Now add like terms \[3t-42-5t-60\]\[\color{red} {3t}\color{blue} {-42}\color{red} {-5t}\color{blue} {-60}\]\[\color{red} {3t-5t}\color{blue} {-42-60}\]\[\color{red} {-2t}\color{blue} {-102}\]there is the final answer.

Answer 14

ok i have to go to bed night thank you soooo much i might pass the quarter thx

Answer 15

Good LUCK!

Answer 16

thx night

Answer 17

U2