IF the length of one base of a trapezoid is 5, the length of the other base is 2x+7, and the length of the midsegment is 6x-24, what is the value of x? show all work that leads to your answer. Help Please:)
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OpenStudy (anonymous):
@Mertsj
@SolomonZelman
@Loser66
Help Guys pleasee lol
OpenStudy (mertsj):
The midsegment is the average of the two bases.
OpenStudy (anonymous):
So I could devide by one of the bases to find the other?
OpenStudy (mertsj):
Do you know how to find an average?
OpenStudy (anonymous):
Not really
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OpenStudy (mertsj):
What is the average of 6 and 4?
OpenStudy (anonymous):
5
OpenStudy (mertsj):
How did you get that?
OpenStudy (anonymous):
(6+4)/2
OpenStudy (mertsj):
Do that with the 2 bases of the trapezoid
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OpenStudy (anonymous):
so (5+2x+7)/2?
OpenStudy (mertsj):
yes
OpenStudy (anonymous):
My calculator says 10.89
OpenStudy (mertsj):
So I guess you skipped school the day they had the lesson about "only like terms can be added"?
OpenStudy (anonymous):
Oh lol, 13+2x/2 then lol
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OpenStudy (mertsj):
7+5=12
OpenStudy (anonymous):
Yes, yes it is lol
OpenStudy (mertsj):
\[\frac{2x+12}{2}\]
Simplify that
OpenStudy (anonymous):
1x+6?
OpenStudy (mertsj):
Yes. That is the average of the two bases.
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OpenStudy (anonymous):
Would that be my answer?
OpenStudy (mertsj):
The midsegment is the average of the two bases.
OpenStudy (mertsj):
What does the problem say the midsegment is?
OpenStudy (anonymous):
6x-24
OpenStudy (mertsj):
And what is the average of the two bases?
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OpenStudy (anonymous):
1x+6
OpenStudy (mertsj):
The average of the two bases is equal to the midsegment.
Write that equation.
OpenStudy (anonymous):
6x-24=1x+6
OpenStudy (mertsj):
Solve that equation
OpenStudy (anonymous):
6x=1x+30
5x=30
x=6
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