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2x+3>1 and 5x-9<6
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2x + 3 > 1 2x>1-3 2x > -2 x> -1 5x - 9 ≤ 6 5x ≤6+9 5x≤15 x≤3 now as this is an"AND situation you need to see the overlap of region on the number line, so put open circle at -1 and an arrow gettign bigger from that and a closed circle at 3 and arrow less than that. so the solution interval s shown by ( -1, 3]
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