Question

Given that Sin 0=3/5, find the values of the other five triganomic functions

Answer 1

Given Sin θ=3/5
=>we have sin^2θ+cos^2θ=1
=>(3/5)^2+cos^2θ=1
=>cos^2θ=1-(9/25)
=>cos^2θ=16/25
=>cos θ=4/5
we have tan θ=sin θ/cos θ
=>tan θ=(3/5)/(4/5)
=>tan θ=3/4
=>cot θ=1/tan θ
=>cot θ=1/(3/4)
=>cot θ=4/3
=>cosec θ= 1/sin θ
=>cosec θ=1/(3/5)
=>cosec θ=5/3
=>sec θ=1/cos θ
=>sec θ=1/(4/5)
=>sec θ=5/4


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