Question

I give medals

Answer 1

Find the lengths of the sides of a triangle with vertices: (0, 0), (5, 0), (5, 12).(1 point)

Answer 2

There are three points and let's name them A, B and C

A(0,0)
B(5,0)
C(5,12)

Do you agree, that the sides of triangle are formed of AB. BC and AC?

Answer 3

i agree

Answer 4

There is a formula, which let's you know the distance of AB, BC and AC:

\[AB=\sqrt{((x _{2}-x1))^2+((y _{2}-y _{1}))^2}\]

A(x1,y1) is the same as A(0,0)
B(x2,y2) is the same as B(5,0) so we get:
\[AB=\sqrt{((0-0))^2+(5-0)^2}=\sqrt{25}=5\]

so one side AB=5. Can you find BC and AC?