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If the length of a large banner is 4x + 5 and the width is half as long, what is the area? A. 6x² + 20x + 12.5 B. 8x² + 17x + 12.5 C. 8x² + 20x + 12.5 D. 8x² + 22x + 12.5
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do 4x+5 times 4x+5/2
4x+5 times (4x+5)/2 i mean
\[(4x + 5) \times [\frac{ (4x + 5) }{ 2 }] = A\]
Area is =length*width given len=(4x+5)*{(4x+5)/2}=.......,
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