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anyone help use the formula to evaluate the series -3+6-12+24-..-a7
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Summation (-1)^n(2n)(3/2)
\[\sum_{n=0}^{\infty}((-1)^n*(2n)(3/2))\]
is that the answer ??
i dont know how to do this at all
Don't start the summation from 0 like I did though, start it at 1. If you start at 0 your first term would be 0.
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This is like art, there is no one way to do it, you just start by analyzing what's happening and take off from there. One step at a time, until it all works out.
i dont understand how to do this problem at all
can you teach me how to do this problem from begining to end
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